2(3-x)=4(4x+^)

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Solution for 2(3-x)=4(4x+^) equation: 



2(3-x)=4(4x+^)

We move all terms to the left:

2(3-x)-(4(4x+^))=0

We add all the numbers together, and all the variables

2(-1x+3)-(4(4x+^))=0

We multiply parentheses

-2x-(4(4x+^))+6=0



We calculate terms in parentheses: -(4(4x+^)), so:

4(4x+^)

We multiply parentheses

16x+

We add all the numbers together, and all the variables

16x

Back to the equation:

-(16x)



We add all the numbers together, and all the variables

-18x+6=0

We move all terms containing x to the left, all other terms to the right

-18x=-6

x=-6/-18

x=1/3

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